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[ .. KEMBALI ]
📄 access-error.js
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📁 action/
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📄 actions.js
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📄 and-add-parent-to-errors.js
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📄 and-finish-tracker.js
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📄 and-ignore-errors.js
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📄 audit.js
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📄 check-permissions.js
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📄 copy-tree.js
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📄 decompose-actions.js
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📄 deps.js
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📄 diff-trees.js
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📄 exists.js
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📄 flatten-tree.js
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📄 fund.js
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📄 get-requested.js
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📄 has-modern-meta.js
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📄 inflate-bundled.js
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📄 inflate-shrinkwrap.js
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📄 is-dev-dep.js
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📄 is-extraneous.js
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📄 is-fs-access-available.js
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📄 is-only-dev.js
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📄 is-only-optional.js
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📄 is-opt-dep.js
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📄 is-prod-dep.js
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📄 module-staging-path.js
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📄 mutate-into-logical-tree.js
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📄 node.js
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📄 read-shrinkwrap.js
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📄 realize-shrinkwrap-specifier.js
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📄 report-optional-failure.js
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📄 save.js
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📄 update-package-json.js
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📄 validate-args.js
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📄 validate-tree.js
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📄 writable.js
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SAVING...
BERHASIL DIUBAH!
EDITING: is-only-dev.js
'use strict' module.exports = isOnlyDev const moduleName = require('../utils/module-name.js') const isDevDep = require('./is-dev-dep.js') const isProdDep = require('./is-prod-dep.js') // Returns true if the module `node` is only required direcctly as a dev // dependency of the top level or transitively _from_ top level dev // dependencies. // Dual mode modules (that are both dev AND prod) should return false. function isOnlyDev (node, seen) { if (!seen) seen = new Set() return node.requiredBy.length && node.requiredBy.every(andIsOnlyDev(moduleName(node), seen)) } // There is a known limitation with this implementation: If a dependency is // ONLY required by cycles that are detached from the top level then it will // ultimately return true. // // This is ok though: We don't allow shrinkwraps with extraneous deps and // these situation is caught by the extraneous checker before we get here. function andIsOnlyDev (name, seen) { return function (req) { const isDev = isDevDep(req, name) const isProd = isProdDep(req, name) if (req.isTop) { return isDev && !isProd } else { if (seen.has(req)) return true seen.add(req) const result = isOnlyDev(req, seen) seen.delete(req) return result } } }
SIMPAN PERUBAHAN